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1951 AHSME Problems/Problem 26

Revision as of 21:38, 10 November 2013 by Fadebekun (talk | contribs) (Created page with "==Problem== In the equation <math>\frac {x(x - 1) - (m + 1)}{(x - 1)(m - 1)} = \frac {x}{m}</math> the roots are equal when <math> \textbf{(A)}\ m = 1\qquad\textbf{(B)}\ m =\fr...")
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Problem

In the equation $\frac {x(x - 1) - (m + 1)}{(x - 1)(m - 1)} = \frac {x}{m}$ the roots are equal when

$\textbf{(A)}\ m = 1\qquad\textbf{(B)}\ m =\frac{1}{2}\qquad\textbf{(C)}\ m = 0\qquad\textbf{(D)}\ m =-1\qquad\textbf{(E)}\ m =-\frac{1}{2}$

Solution

Unsolved

See Also

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