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2012 AMC 10B Problems/Problem 16

Revision as of 21:15, 16 February 2013 by Willalphagamma (talk | contribs)

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To determine the area of the figure, you can connect the centers of the circles to form an equilateral triangle of length $4$. Find the area of this triangle to include the figure formed in between the circles. This area is $4\sqrt{3}$.


To find the area of the remaining sectors, notice that the sectors have a central angle of 300 because 60 degrees were "used up" for the triangle. The area of one sector is $2^2 \pi * 5/6 = 10\pi/3$. Then this area is multiplied by three to find the total area of the sectors (10 pi). This result is added to area of the equilateral triangle to get a final answer of $10\pi + 4\sqrt3$.

This means (A) is the right answer.

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