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1989 AHSME Problems/Problem 6

Revision as of 05:03, 19 February 2012 by Ckorr2003 (talk | contribs) (Created page with "If <math>a,b>0</math> and the triangle in the first quadrant bounded by the co-ordinate axes and the graph of <math>ax+by=6</math> has area 6, then <math>ab=</math> <math> \math...")
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If $a,b>0$ and the triangle in the first quadrant bounded by the co-ordinate axes and the graph of $ax+by=6$ has area 6, then $ab=$

$\mathrm{(A) \ 3 } \qquad \mathrm{(B) \ 6 } \qquad \mathrm{(C) \ 12 } \qquad \mathrm{(D) \ 108 } \qquad \mathrm{(E) \ 432 }$

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