1989 AHSME Problems/Problem 26

Revision as of 04:59, 19 February 2012 by Ckorr2003 (talk | contribs) (Created page with "A regular octahedron is formed by joining the centers of adjoining faces of a cube. The ratio of the volume of the octahedron to the volume of the cube is <math> \mathrm{(A) \fr...")
(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)

A regular octahedron is formed by joining the centers of adjoining faces of a cube. The ratio of the volume of the octahedron to the volume of the cube is

$\mathrm{(A) \frac{\sqrt{3}}{12} } \qquad \mathrm{(B) \frac{\sqrt{6}}{16} } \qquad \mathrm{(C) \frac{1}{6} } \qquad \mathrm{(D) \frac{\sqrt{2}}{8} } \qquad \mathrm{(E) \frac{1}{4} }$