2003 AMC 8 Problems/Problem 20

Solution

Imagine the clock as a circle. By $4:20$ , the hour hand would have moved $\frac{1}{3}$ way towards the five since $\frac{20}{60}$ is reducible to $\frac{1}{3}$ . The central angle formed between $4$ and $5$ would be $30$ degrees since the angle between $12$ and $6$ is $180$ degrees and $\frac{180}{6} = 30$ Since the central angle formed from $4:20$ is a third of the central angle formed between $4$ and $5$ , $30$ degrees, the answer is $\boxed{\textbf{(D)}\ 10}$

2003 AMC 8 (Problems • Answer Key • Resources)
Preceded by Problem 19	Followed by Problem 21
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
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2003 AMC 8 Problems/Problem 20

Solution