AoPS Wiki talk:Problem of the Day/July 26, 2011
Revision as of 21:39, 25 July 2011 by Kingofmath101 (talk | contribs) (July 26, 2011- Solution to the Problem of the Day)
Solution:
Move all of the terms to one side:
Now, factor:
Multiply by and get rid of the negative in front of :
One possibility is that , yielding us an infinite number of possibilities, giving us an answer of .