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AoPS Wiki talk:Problem of the Day/July 4, 2011

Revision as of 00:36, 4 July 2011 by GeoffreyS (talk | contribs)

Problem

AoPSWiki:Problem of the Day/July 4, 2011

Solution

$3^x-3 \equiv 0 \mod 16 \Rightarrow 3^x \equiv 3 \mod 16$ So $3^x$ cycles through 3,9,11,1 mod 16, $x = 1$ doesn't work so try $x = 5$ which works and we're done This Problem of the Day needs a solution. If you have a solution for it, please help us out by adding it.

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