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AoPS Wiki:Problem of the Day/June 18, 2011

< AoPS Wiki:Problem of the Day
Revision as of 17:06, 17 June 2011 by Btilm305 (talk | contribs) (Protected "AoPSWiki:Problem of the Day/June 18, 2011": Problem of the Day ([edit=sysop] (indefinite) [move=sysop] (indefinite)))
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In trapezoid $ABCD$, $m\angle A=m\angle D=90^{\circ}$. Base $AB$ has a length of $9$ while base $CD$ has a length of $15$. Diagonals $AC$ and $BD$ meet at point $X$. If the perimeter of the trapezoid is $42$, find the distance from $X$ to $CD$.

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