1986 AJHSME Problems/Problem 13
Problem
The perimeter of the polygon shown is
Solution
Note: I'm assuming all concave angles are right angles.
At first, we may immediately put down E, because of course we don't know many of the segments. But let's give it a shot.
For the segments parallel to the side with side length 8, let's call those two segments and , the longer segment being b, the shorter one being a.
For the segments parallel to the side with side length 6, let's call those two segments and , the longer segment being d, the shorter one being c.
So the perimeter of the polygon would be...
And it looks like we're stuck. But wait!
Notice that , and .
Now we plug those in...
28 is C.