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1985 AJHSME Problems/Problem 8

Revision as of 20:35, 12 January 2009 by 5849206328x (talk | contribs) (New page: ==Problem== If <math>a = - 2</math>, the largest number in the set <math>\{ - 3a, 4a, \frac {24}{a}, a^2, 1\}</math> is <math>\text{(A)}\ -3a \qquad \text{(B)}\ 4a \qquad \text{(C)}\ \fr...)
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Problem

If $a = - 2$, the largest number in the set $\{ - 3a, 4a, \frac {24}{a}, a^2, 1\}$ is

$\text{(A)}\ -3a \qquad \text{(B)}\ 4a \qquad \text{(C)}\ \frac {24}{a} \qquad \text{(D)}\ a^2 \qquad \text{(E)}\ 1$

Solution

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See Also

1985 AJHSME Problems

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