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2005 iTest Problems/Problem 4

Revision as of 02:50, 9 December 2024 by Almond oil (talk | contribs)
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Taking one factor of $2005$ as a base, the other is split into $5 ^1 \cot{ 401 ^1} = 2005$. This means $2005$ has $(1 + 1)\cdot{(1 + 1)} = 4$ divisors. Each of these divisors represents a multiple of $2005$, meaning the answer is $\boxed{4}$

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