1959 AHSME Problems/Problem 22
Problem
The line joining the midpoints of the diagonals of a trapezoid has length 
. If the longer base is 
then the shorter base is: 
Solution
Let x be the length of the shorter base. 3 = (97 - x)/2
6 = 97 - x
x = 91
Thus, 91.
See also
| 1959 AHSC (Problems • Answer Key • Resources) | ||
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Followed by Problem 23 | |
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The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
