1970 AMC 12 Problems/Problem 2

Problem

A square and a circle have equal perimeters. The ratio of the area of the circle to the area of the square is

$\mathrm{(A)}\ \frac{2}{\pi}\qquad \mathrm{(B)}\ \frac{\pi}{\sqrt{2}}\qquad \mathrm{(C)}\ \frac{4}{5}\qquad \mathrm{(D)}\ \frac{5}{6}\qquad \mathrm{(E)}\ \frac{7}{8}$

Page

Toolbox

Search

1970 AMC 12 Problems/Problem 2

Problem

Solution