2000 AIME II Problems/Problem 9

Revision as of 17:40, 3 January 2008 by Thorn (talk | contribs) (Solution)

Problem

Given that $z$ is a complex number such that $z+\frac 1z=2\cos 3^\circ$, find the least integer that is greater than $z^{2000}+\frac 1{z^{2000}}$.

Solution

Note that if z is on the unit circle in the complex plane, then $z = e^{i\theta} = cos \theta + isin \theta$ and $\frac 1z= e^{-i\theta} = cos \theta - isin \theta$

Let $z = a + bi$

See also

2000 AIME II (ProblemsAnswer KeyResources)
Preceded by
Problem 8
Followed by
Problem 10
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
All AIME Problems and Solutions