2024 AMC 8 Problems/Problem 2

Revision as of 21:36, 7 February 2024 by Morgansu (talk | contribs) (Solution 2)

Knock knock

whos there

Solution 3

Convert all of them into the same demoninator of $1100$. We have $\frac{4400}{1100} + \frac{2750}{1100} + \frac{44}{1100} = \frac{7194}{1100} = \boxed{\textbf{(C) }6.54}$ ~andliu766


Solution 4(fastest)

Use 4400 as the common denominator.

$\frac{17600}{4400} + \frac{11000}{4400} + \frac{176}{4400} = \frac{17600+11000+176}{4400} = \frac{28776}{4400} =  \boxed{\textbf{(C) }6.54}$

-thebanker88

Video Solution 1 (easy to digest) by Power Solve

https://www.youtube.com/watch?v=dQw4w9WgXcQ

Video Solution by Math-X (First fully understand the problem!!!)

https://www.youtube.com/watch?v=dQw4w9WgXcQ ~Rick Atsley

Note: thiss link was made by @iamatinychildwhoisincapableofdoinganything,existentornonexistent

Video Solution by NiuniuMaths (Easy to understand!)

https://www.youtube.com/watch?v=dQw4w9WgXcQ

~NiuniuMaths

Video Solution 2 by SpreadTheMathLove

https://www.youtube.com/watch?v=dQw4w9WgXcQ

Video Solution by CosineMethod [🔥Fast and Easy🔥]

https://www.youtube.com/watch?v=dQw4w9WgXcQ

Video Solution by Interstigation

https://youtu.be/ktzijuZtDas&t=108

See Also

2024 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png