2012 OIM Problems/Problem 2

Revision as of 14:41, 14 December 2023 by Tomasdiaz (talk | contribs) (Created page with "== Problem == A positive integer is ''bisummed'' if it can be written as the sum of two integers positive numbers that have the same sum of their digits. For example, 2012 is...")
(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)

Problem

A positive integer is bisummed if it can be written as the sum of two integers positive numbers that have the same sum of their digits. For example, 2012 is bisumed because $2012 = 2005 + 7$ and both 2005 and 7 have their digit sum equal to 7. Find all the positive integers that are not 'bisummed.

~translated into English by Tomas Diaz. ~orders@tomasdiaz.com

Solution

This problem needs a solution. If you have a solution for it, please help us out by adding it.

See also

OIM Problems and Solutions