2001 OIM Problems/Problem 1
Problem
We say that a natural number 
is "çharrúa" if it simultaneously satisfies the following conditions:
- All digits of
are greater than 1.
- Whenever four digits of are multiplied, a divisor of is obtained.
Show that for each natural number 
there is a çharrúa number with more than digits.
~translated into English by Tomas Diaz. ~orders@tomasdiaz.com
Solution
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