2023 AMC 12B Problems/Problem 18
Revision as of 17:36, 15 November 2023 by Professorchenedu (talk | contribs) (Created page with "==Solution== Denote by <math>A_i</math> the average of person with initial <math>A</math> in semester <math>i \in \left\{1, 2 \right\}</math> Thus, <math>Y_1 = Z_1 + 3</math>...")
Solution
Denote by the average of person with initial in semester Thus, , , .
Denote by the average of person with initial in the full year. Thus, can be any number in and can be any number in .
Therefore, the impossible solution is \boxed{\textbf{(A) Yolanda's quiz average for the academic year was 22 points higher than Zelda's.}}
~Steven Chen (Professor Chen Education Palace, www.professorchenedu.com)