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2005 PMWC Problems/Problem I14

Revision as of 20:33, 21 August 2022 by Shreyaa07 (talk | contribs) (→‎Problem)
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Solution

From the given, we have the equations

\[3g = 6b \Longrightarrow g = 2b\] \[2y = 5b \Longrightarrow y = \frac{5}{2}b\] \[4w = 6b \Longrightarrow w = \frac{3}{2}b\]

Substuting gives us $4g + 2y + 2w = 4(2b) + 2\left(\frac{5}{2}b\right) + 2\left(\frac{3}{2}b\right) = 16b$, and our answer is 16.

See also

2005 PMWC (Problems)
Preceded by
Problem I13 		Followed by
Problem I15
I: 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15
T: 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10
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