2009 AMC 10A Problems/Problem 8

Revision as of 18:48, 2 August 2022 by Zlrara01 (talk | contribs) (Solution 2)

Problem 8

Three Generations of the Wen family are going to the movies, two from each generation. The two members of the youngest generation receive a $50$% discount as children. The two members of the oldest generation receive a $25\%$ discount as senior citizens. The two members of the middle generation receive no discount. Grandfather Wen, whose senior ticket costs $$6.00$, is paying for everyone. How many dollars must he pay?

$\mathrm{(A)}\ 34 \qquad \mathrm{(B)}\ 36 \qquad \mathrm{(C)}\ 42 \qquad \mathrm{(D)}\ 46 \qquad \mathrm{(E)}\ 48$

Solution

A senior ticket costs $$6.00$, so a regular ticket costs $6 \cdot \frac{1}{\frac{3}{4}}\:=\:6\cdot\frac{4}{3}\:=\:8$ dollars. Therefore children's tickets cost half that, or $$4.00$, so we have:

$2(6+8+4)\:=\:36$

So Grandfather Wen pays $$36$, or $\fbox{B}$.

Solution 2

Using average, we know that assuming the middle-aged people's ticket cost x dollars, 2\cdot(100%x+75%x+50%x). We average this into 2*(75%x+75%x+75%x). We know that 75%x=6.00, which means $6\cdot6$ is the answer, or 36. -RealityWrites

See Also

2009 AMC 10A (ProblemsAnswer KeyResources)
Preceded by
Problem 7
Followed by
Problem 9
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png