2018 AMC 10B Problems/Problem 1

The following problem is from both the 2018 AMC 12B #1 and 2018 AMC 10B #1, so both problems redirect to this page.

Problem

Kate bakes a $20$ -inch by $18$ -inch pan of cornbread. The cornbread is cut into pieces that measure $2$ inches by $2$ inches. How many pieces of cornbread does the pan contain?

$\textbf{(A) } 90 \qquad \textbf{(B) } 100 \qquad \textbf{(C) } 180 \qquad \textbf{(D) } 200 \qquad \textbf{(E) } 360$

Solution 1

The area of the pan is $20\cdot18=360$ . Since the area of each piece is $2\cdot2=4$ , there are $\frac{360}{4} = \boxed{\textbf{(A) } 90}$ pieces.

Solution 2

By dividing each of the dimensions by $2$ , we get a $10\times9$ grid that makes $\boxed{\textbf{(A) } 90}$ pieces.

Video Solution

https://youtu.be/o5MUHOmF1zo

~savannahsolver

2018 AMC 10B (Problems • Answer Key • Resources)
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All AMC 10 Problems and Solutions

2018 AMC 12B (Problems • Answer Key • Resources)
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All AMC 12 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

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2018 AMC 10B Problems/Problem 1

Contents

Problem

Solution 1

Solution 2

Video Solution

See Also