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1963 TMTA High School Algebra I Contest Problem 27

Revision as of 10:15, 2 February 2021 by Coolmath34 (talk | contribs) (Created page with "== Problem == If <math>A</math> varies directly as <math>B,</math> and if <math>A=5</math> when <math>B=3,</math> then the value of <math>A</math> when <math>B=15</math> is:...")
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Problem

If $A$ varies directly as $B,$ and if $A=5$ when $B=3,$ then the value of $A$ when $B=15$ is:

$\text{(A)} \quad 25 \quad \text{(B)} \quad 50 \quad \text{(C)} \quad 75 \quad \text{(D)} \quad 3/5 \quad \text{(E)} \quad 5/3$

Solution

Write this as a proportion: $\frac{A}{B}=\frac{5}{3}=\frac{x}{15}.$ We get $A = \boxed{\text{(A)} \quad 25}.$

See Also

1963 TMTA High School Mathematics Contests (Problems)
Preceded by
Problem 26 		TMTA High School Mathematics Contest Past Problems/Solutions Followed by
Problem 28
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