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1963 TMTA High School Algebra I Contest Problem 4

Revision as of 21:25, 1 February 2021 by Coolmath34 (talk | contribs) (Created page with "== Problem == The product of <math>3.5 \times 10^3</math> and <math>1.8 \times 10^4</math> is: <math>\text{(A)} 5.3 \times 10^7 \quad \text{(B)} \quad 6.3 \times 10^7 \quad \...")
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Problem

The product of $3.5 \times 10^3$ and $1.8 \times 10^4$ is:

$\text{(A)} 5.3 \times 10^7 \quad \text{(B)} \quad 6.3 \times 10^7 \quad \text{(C)} \quad 6.3 \times 10^{12} \quad \text{(D)} \quad \frac 5.3 \times 10^1 \quad \text{(E) NOTA}$

Solution

Multiply: \[(3.5 \cdot 10^3)(1.8 \cdot 10^4) = (3.5 \cdot 1.8)(10^3 \cdot 10^4) = 6.3 \cdot 10^7\] The answer is $\boxed{\text{(B)}}.$

See Also

1963 TMTA High School Mathematics Contests (Problems)
Preceded by
Problem 3 		TMTA High School Mathematics Contest Past Problems/Solutions Followed by
Problem 5
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