1967 AHSME Problems/Problem 14
Problem
Let , . If , then can be expressed as
Solution
Let and
then
and
By solving we find--
However and
Therefore , and
Thus, the only solutions are , and
So there are only 2 solutions
See also
1967 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 13 |
Followed by Problem 15 | |
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All AHSME Problems and Solutions |
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