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1956 AHSME Problems/Problem 8

Revision as of 13:43, 31 August 2019 by Mr.peppa (talk | contribs) (Created page with "== Solution == Simple substitution yields <cmath>8 \cdot 2^{x} = 5^{0}</cmath> Reducing the equation gives <cmath>8 \cdot 2^{x} = 1</cmath> Dividing by 8 gives <cmath>2^{x}=\...")
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Solution

Simple substitution yields \[8 \cdot 2^{x} = 5^{0}\] Reducing the equation gives \[8 \cdot 2^{x} = 1\] Dividing by 8 gives 

\[2^{x}=\frac{1]{8}\] (Error compiling LaTeX. Unknown error_msg)

This simply gives that $x=-3$ Therefore, the answer is $\fbox{(b) -30}$

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