Proof of the Polynomial Remainder Theorem

The remainder theorem states when a polynomial denoted as $f(x)$ is divided by $x-a$ for some value of $x$ , whether real or unreal, the remainder of $\frac{f(x)}{x-a}=f(a)$ Written below is the proof of the polynomial remainder theorem.

All polynomials can be written in the form $f(x)=d(x)\cdot\q(x)+r(x)$ (Error compiling LaTeX. Unknown error_msg), where $d(x)$ is the divisor of the function/polynomial $f(x)$ , $q(x)$ is the quotient. amd $r(x)$ is the remainder. Because the $deg r=0$ or $deg r\less\deg d$ (Error compiling LaTeX. Unknown error_msg) and the $deg d=1$ , degrees must be whole numbers, and so $deg r=0$ . So to speak, $r(x)$ is a constant. We denote this constant $b$ .

Knowing this, we can write

$f(x)=d(x)\cdot\q(x)+b$ (Error compiling LaTeX. Unknown error_msg)

$f(x)=(x-a)\cdot\q(x)+b$ (Error compiling LaTeX. Unknown error_msg)

$f(a)=(a-a)\cdot\q(a)+b$ (Error compiling LaTeX. Unknown error_msg)

$f(a)=b$

We have hereby proven when the quantity $x-a$ is divided into a polynomial $f(x)$ of any degree, the value of $f(a)=b$ , where b is the remainder. The remainder must be a constant because $deg r=0$ .

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Proof of the Polynomial Remainder Theorem