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1977 AHSME Problems/Problem 2

Revision as of 11:34, 18 November 2016 by E power pi times i (talk | contribs) (→‎Solution)

Solution

Solution by e_power_pi_times_i

Equilateral triangles can be in different sizes, therefore they are not $\boxed{\textbf{(D)}\ \text{congruent to each other}}$

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