Besot Power Series

Theorem

Besot's Power Series Theorem states that $\sum\limits_{i=1}^m n^{a+(i-1)z} = \frac{n^{a+mz}-n^a}{n^z-1}$

Let there be a sum $n^a + n^{a+z} + ... n^{a+(m-1)z} = \sum\limits_{i=1}^m n^{a+(i-1)z} = s$

$s = \sum\limits_{i=1}^m n^{a+(i-1)z}$

$sn^z = \sum\limits_{i=1}^m n^{a+iz}$

$sn^z-s = \sum\limits_{i=1}^m n^{a+iz} - \sum\limits_{i=1}^m n^{a+(i-1)z}$

$s(n^z-1) = n^{a+mz}-n^a$

$s = \frac{n^{a+mz}-n^a}{n^z-1}$

$\boxed{\frac{n^{a+mz}-n^a}{n^z-1}}$

What is $8(3^3+3^5+3^7+3^9)+27$

$\sum\limits_{i=1}^{2016} n^i = n^{2017}$ . What is $n$ ?