2016 AMC 12A Problems/Problem 3

Solution

$\text{rem}\left(\frac{3}{8},-\frac{2}{5}\right)$ $=\frac{3}{8}-\left(-\frac{2}{5}\right)\lfloor\frac{\frac{3}{8}}{-\frac{-2}{5}}\rfloor$ $=\frac{3}{8}+\left(\frac{2}{5}\right)\lfloor -\frac{15}{16}\rfloor$ $=\frac{3}{8}+\left(\frac{2}{5}\right)\left(-1\right)$ $=\frac{3}{8}-\frac{2}{5}$ $=\boxed{\textbf{(B)}-\frac{1}{40}}$ Notice that it would not matter if either $-\frac{2}{5}$ or $\frac{2}{5}$ were used.

Page

Toolbox

Search

2016 AMC 12A Problems/Problem 3

Solution