2015 AMC 10A Problems/Problem 10

Revision as of 14:25, 4 February 2015 by Happycowzh (talk | contribs) (Solution)

Problem

How many rearrangements of $abcd$ are there in which no two adjacent letters are also adjacent letters in the alphabet? For example, no such rearrangements could include either $ab$ or $ba$.

$\textbf{(A)}\ 0\qquad\textbf{(B)}\ 1\qquad\textbf{(C)}\ 2\qquad\textbf{(D)}}\ 3\qquad\textbf{(E)}\ 4$ (Error compiling LaTeX. Unknown error_msg)


Solution

Observe that we can't begin a rearrangement with either a or d, leaving bcd and abc, respectively.

Starting with b, there is only one rearrangement: $bdac$. Similarly, there is only one rearrangement when we start with c: $cadb$.

Therefore, our answer must be $\boxed{\textbf{(C) }2}$.