1990 AHSME Problems/Problem 20

Problem

In the figure $ABCD$ is a quadrilateral with right angles at $A$ and $C$ . Points $E$ and $F$ are on $\overline{AC}$ , and $\overline{DE}$ and $\overline{BF}$ are perpendicual to $\overline{AC}$ . If $AE=3, DE=5,$ and $CE=7$ , then $BF=$

$\text{(A) } 3.6\quad \text{(B) } 4\quad \text{(C) } 4.2\quad \text{(D) } 4.5\quad \text{(E) } 5$

Solution

$\fbox{C}$

1990 AHSME (Problems • Answer Key • Resources)
Preceded by Problem 19	Followed by Problem 21
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1990 AHSME Problems/Problem 20

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