1991 AHSME Problems/Problem 13

Problem

Horses $X,Y$ and $Z$ are entered in a three-horse race in which ties are not possible. The odds against $X$ winning are $3:1$ and the odds against $Y$ winning are $2:3$ , what are the odds against $Z$ winning? (By "odds against $H$ winning are $p:q$ " we mean the probability of $H$ winning the race is $\frac{q}{p+q}$ .)

$\text{(A) } 3:20\quad \text{(B) } 5:6\quad \text{(C) } 8:5\quad \text{(D) } 17:3\quad \text{(E) } 20:3$

Solution

$\fbox{E}$

1991 AHSME (Problems • Answer Key • Resources)
Preceded by Problem 12	Followed by Problem 14
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1991 AHSME Problems/Problem 13

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