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1951 AHSME Problems/Problem 49

Revision as of 13:45, 13 April 2012 by AplayerDanny (talk | contribs) (Created page with "Two equations can be written: <math>x^2 + 4y^2 = 40</math> and <math>4x^2+y^2= 25</math> Add them together and get <math>5x^2+5y^2=65</math> then <math>x^2+y^2=13</math> Multiply...")
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Two equations can be written: $x^2 + 4y^2 = 40$ and $4x^2+y^2= 25$ Add them together and get $5x^2+5y^2=65$ then $x^2+y^2=13$ Multiply them by 4 to get the square of the value of the hypotenuse which is 52. Take the square root and get the answer $2SQRT13$

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