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2013 AMC 12A Problems/Problem 4

Revision as of 21:17, 6 February 2013 by Epicwisdom (talk | contribs) (LaTeX formatting)

$\frac{2^{2014}+2^{2012}}{2^{2014}-2^{2012}}$

We can factor a 2^2012 out of the numerator and denominator to obtain

$\frac{2^{2012}*(2^2+1)}{2^{2012}*(2^2-1)}$

Both the (2^2012) terms cancel, so we get

$\frac{(2^2+1)}{(2^2-1)}=\frac{5}{3}$, which is C

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