2004 AMC 8 Problems/Problem 5

Problem

The losing team of each game is eliminated from the tournament. If sixteen teams compete, how many games will be played to determine the winner?

$\textbf{(A)}4\qquad\textbf{(B)}7\qquad\textbf{(C)}8\qquad\textbf{(D)}15\qquad\textbf{(E)}16$

Solution

There will be $8$ games the first round, $4$ games the second round, $2$ games the third round, and $1$ game in the final round, giving us a total of $8+4+2+1=15$ games. $\boxed{\textbf{(D)}\ 15}$

Page

Toolbox

Search

2004 AMC 8 Problems/Problem 5

Problem

Solution