2004 AMC 8 Problems/Problem 4

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Problem

Ms. Hamilton’s eighth-grade class wants to participate in the annual three-person-team basketball tournament.

Lance, Sally, Joy, and Fred are chosen for the team. In how many ways can the three starters be chosen?

$\textbf{(A)}2\qquad\textbf{(B)}4\qquad\textbf{(C)}6\qquad\textbf{(D)}8\qquad\textbf{(E)}10$

Solution

There are $\binom{5}{3}$ ways to choose three starters. Thus the answer is $\boxed{\textbf{(B)}\ 4}$