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1993 AJHSME Problems/Problem 6

Revision as of 20:18, 28 July 2011 by Math Kirby (talk | contribs) (Created page with "== Problem 6 == A can of soup can feed <math>3</math> adults or <math>5</math> children. If there are <math>5</math> cans of soup and <math>15</math> children are fed, then how...")
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Problem 6

A can of soup can feed $3$ adults or $5$ children. If there are $5$ cans of soup and $15$ children are fed, then how many adults would the remaining soup feed?

$\text{(A)}\ 5 \qquad \text{(B)}\ 6 \qquad \text{(C)}\ 7 \qquad \text{(D)}\ 8 \qquad \text{(E)}\ 10$

Solution

A can of soup will feed $5$ children so $15$ children are feed by $3$ cans of soup. Therefore, there are $5-3=2$ cans for adults, so $3 \times 2 =\boxed{\text{(B)6}}$ adults are feed.

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