1974 AHSME Problems/Problem 3

Problem

The coefficient of $x^7$ in the polynomial expansion of

$(1+2x-x^2)^4$

is

$\mathrm{(A)\ } -8 \qquad \mathrm{(B) \ }12 \qquad \mathrm{(C) \ } 6 \qquad \mathrm{(D) \ } -12 \qquad \mathrm{(E) \ }\text{none of these}$

Solution

Let's write out the multiplication, so that it becomes easier to see.

$(1+2x-x^2)(1+2x-x^2)(1+2x-x^2)(1+2x-x^2)$

We can now see that the only way to get an $x^7$ is by taking three $-x^2$ and one $2x$ . There are $\binom{4}{1}=4$ way to pick which term the $2x$ comes from, and the coefficient of each one is $(-1)^3(2)=-2$ . Therefore, the coefficient of $x^7$ is $(4)(-2)=-8, \boxed{\text{A}}$ .

1974 AHSME (Problems • Answer Key • Resources)
Preceded by Problem 2	Followed by Problem 4
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30
All AHSME Problems and Solutions

Page

Toolbox

Search

1974 AHSME Problems/Problem 3

Problem

Solution

See Also