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2000 AMC 8 Problems/Problem 16

Revision as of 00:19, 20 June 2011 by CYAX (talk | contribs) (Created page with "The length of the rectangle is 1000/25=40 meters. The perimeter equals 1000/10=100 meters. Perimeter is 2L+2W. Solving for W, we get 10 inches. The area is 40*10=400 square meter...")
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The length of the rectangle is 1000/25=40 meters. The perimeter equals 1000/10=100 meters. Perimeter is 2L+2W. Solving for W, we get 10 inches. The area is 40*10=400 square meters or C.

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