1999 AMC 8 Problems/Problem 23
Revision as of 14:28, 17 June 2011 by Mrdavid445 (talk | contribs)
Since the squares have side length 
, the area of the entire square is 
.
The segments divide the square into 3 equal parts, so the area of each part is .
The base of a triangle is , so the height must be 
.
.
$CM=\sqrt {3^2+2^2$ (Error compiling LaTeX. Unknown error_msg)} = 
-Mrdavid445
