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2002 AMC 8 Problems/Problem 4

Revision as of 12:10, 17 June 2011 by Hydroxide (talk | contribs) (Created page with "The palindrome right after 2002 is 2112. The product of the digits of 2112 is <math>\boxed{4}</math>.")
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The palindrome right after 2002 is 2112. The product of the digits of 2112 is $\boxed{4}$.

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