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2010 AMC 10B Problems/Problem 8

Revision as of 20:37, 10 January 2011 by Thegoldenratio (talk | contribs) (Created page with 'We see how many common integer factors 48 and 64 share. Of the factors of 48 - 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48; only 1, 2, 4, and 8 are factors of 64. So there are <math>\bo…')
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We see how many common integer factors 48 and 64 share. Of the factors of 48 - 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48; only 1, 2, 4, and 8 are factors of 64. So there are $\boxed{4}$ possibilities for the ticket price.

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