1989 AJHSME Problems/Problem 4
Revision as of 16:54, 28 May 2009 by 5849206328x (talk | contribs) (New page: ==Problem== Estimate to determine which of the following numbers is closest to <math>\frac{401}{.205}</math>. <math>\text{(A)}\ .2 \qquad \text{(B)}\ 2 \qquad \text{(C)}\ 20 \qquad \text...)
Problem
Estimate to determine which of the following numbers is closest to .
Solution
is around and is around $.2 so the fraction is approximately
See Also
1989 AJHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 3 |
Followed by Problem 5 | |
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