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1991 AJHSME Problems/Problem 10

Revision as of 18:00, 8 February 2009 by Boo (talk | contribs) (→‎Problem 10)

Problem 10

The area in square units of the region enclosed by parallelogram ABCD, with A(-1,0), B(0,2), C(4,2), D(3,0), is

$\mathrm{(A) \ 6 } \qquad \mathrm{(B) \ 8 } \qquad \mathrm{(C) \ 12 } \qquad \mathrm{(D) \ 15 } \qquad \mathrm{(E) \ 18 }$

Solution

Note the base AD=BC=4 and the height is the y-value of B and C which is 2 $\Rightarrow \text{Area}=2\cdot4=8 \Rightarrow \boxed{B}$

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