2025 AMC 8 Problems/Problem 9

Revision as of 16:25, 2 February 2025 by Xxjellyichanxx (talk | contribs) (Solution 1)

Problem

Ningli looks at the 6 pairs of numbers directly across from each other on a clock. She takes the average of each pair of numbers. What is the average of the resulting 6 numbers?

Amc8 2025 prob9.PNG

$\textbf{(A)}\ 5\qquad \textbf{(B)}\ 6.5\qquad \textbf{(C)}\ 8\qquad \textbf{(D)}\ 9.5 \qquad \textbf{(E)}\ 12$

Solution 1

The answer can be expressed as $(1+7)/2 + (2 + 8)/2 + ... + (6 + 12)/2$, with the whole result divided by 6. Therefore, the answer of the question is the sum of the numbers from 1 through 12 divided by 2 * 6 = 12. The answer is $12/2$ = $6 \times 13$ = $78/12$, leading to the answer $\frac{78}{12}=\boxed{\textbf{(B)}~6.5}$.

~Sigmacuber

Solution 2

The pairs for the opposite numbers on the clock are $(12,6)$, $(1,7)$, $(2,8)$, $(3,9)$, $(4,10)$, and $(5,11)$. The averages of each of these pairs are $9, 4, 5, 6, 7,$ and $8$ respectively. The averages of $9, 4, 5, 6, 7,$ and $8$ are $\frac{39}{6}=\boxed{\textbf{(B)}~6.5}$

~Bepin999

Solution 3 (most efficient solution)

If you read the problem carefully, you will find that it is basically asking for the average of all $12$ numbers. To find the average of all $12$ numbers, you add all the numbers from $1 - 12$ which is $78$, and divide it by $12$ because there are 12 terms, therefore, the answer is $\frac{78}{12}=\boxed{\textbf{(B)}~6.5}$.

~JacQueen2024

Video Solution 1 by SpreadTheMathLove

https://www.youtube.com/watch?v=jTTcscvcQmI

Video Solution (A Clever Explanation You’ll Get Instantly)

https://youtu.be/VP7g-s8akMY?si=QWgBnVJLRi_J9Hox&t=667 ~hsnacademy

Video Solution by Thinking Feet

https://youtu.be/PKMpTS6b988

See Also

2025 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 8
Followed by
Problem 10
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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