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2005 iTest Problems/Problem 4

Revision as of 02:50, 9 December 2024 by Almond oil (talk | contribs) (Created page with "Taking one factor of <math>2005</math> as a base multiple, the other is split into <math>5 ^1 \cdot{ 401 ^1} = 2005</math>. This means <math>2005</math> has <math>(1 + 1)\cdot...")
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Taking one factor of $2005$ as a base multiple, the other is split into $5 ^1 \cdot{ 401 ^1} = 2005$. This means $2005$ has $(1 + 1)\cdot{(1 + 1)} = 4$ divisors. Each of these divisors can be multiplied with the base multiple of $2005$, meaning the answer is $\boxed{4}$

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