1965 AHSME Problems/Problem 16

Problem

Let line $AC$ be perpendicular to line $CE$ . Connect $A$ to $D$ , the midpoint of $CE$ , and connect $E$ to $B$ , the midpoint of $AC$ . If $AD$ and $EB$ intersect in point $F$ , and $\overline{BC} = \overline{CD} = 15$ inches, then the area of triangle $DFE$ , in square inches, is:

$\textbf{(A)}\ 50 \qquad \textbf{(B) }\ 50\sqrt {2} \qquad \textbf{(C) }\ 75 \qquad \textbf{(D) }\ \frac{15}{2}\sqrt{105}\qquad \textbf{(E) }\ 100$

Solution

$\fbox{C}$

1965 AHSC (Problems • Answer Key • Resources)
Preceded by Problem 15	Followed by Problem 17
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1965 AHSME Problems/Problem 16

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