2002 AMC 12P Problems/Problem 18
Problem
If 
are real numbers such that 
, 
and 
, find 
Solution 1
Adding all of the equations gives 
Adding 14 on both sides gives 
Notice that 14 can split into 
and 
which coincidentally makes 
and 
into perfect squares. Therefore, 
An easy solution to this equation is 
and 
Plugging in that solution, we get 
See also
| 2002 AMC 12P (Problems • Answer Key • Resources) | |
| Preceded by Problem 17 |
Followed by Problem 19 |
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| All AMC 12 Problems and Solutions | |
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