2016 AMC 8 Problems/Problem 9

Problem

What is the sum of the distinct prime integer divisors of 735 ?

$\textbf{(A) }9\qquad\textbf{(B) }15\qquad\textbf{(C) }16\qquad\textbf{(D) }49\qquad \textbf{(E) }63$

Solutions

Solution 1

The prime factorization is $735=2^5\times3^2\times7$ . Since the problem is only asking us for the distinct prime factors, we have $2,3,7$ . Their desired sum is then $\boxed{\textbf{(B) }15}$ .

Video Solution (CREATIVE THINKING!!!)

https://youtu.be/GNFnta9MF9E

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Video Solution

https://youtu.be/1KN7OTG3k-0

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2016 AMC 8 (Problems • Answer Key • Resources)
Preceded by Problem 8	Followed by Problem 10
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All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

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