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2024 AMC 8 Problems/Problem 22

Revision as of 15:56, 25 January 2024 by Bs2012 (talk | contribs) (→‎Solution)

Problem 22

Solution

There are about $\dfrac{1}{0.015}=\dfrac{200}{3}$ "full circles" of tape, and with average circumference of $\dfrac{4+2}{2}\pi=3\pi.$ $\dfrac{200}{3}*3\pi=200\pi,$ which means the answer is $600.$

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